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# 钱数转大写def convertNumToChinese(totalPrice):    dictChinese = [u'零',u'壹',u'贰',u'叁',u'肆',u'伍',u'陆',u'柒',u'捌',u'玖']    unitChinese = [u'',u'拾',u'佰',u'仟','',u'拾',u'佰',u'仟']    #将整数部分和小数部分区分开    partA = int(math.floor(totalPrice))    partB = round(totalPrice-partA, 2)    strPartA = str(partA)    strPartB = ''    if partB != 0:        strPartB = str(partB)[2:]    singleNum = []    if len(strPartA) != 0:        i = 0        while i < len(strPartA):            singleNum.append(strPartA[i])            i = i+1    #将整数部分先压再出，因为可以从后向前处理，好判断位数    tnumChinesePartA = []    numChinesePartA = []    j = 0    bef = '0';    if len(strPartA) != 0:        while j < len(strPartA) :            curr = singleNum.pop()            if curr == '0' and bef !='0':                tnumChinesePartA.append(dictChinese[0])                bef = curr            if curr != '0':                tnumChinesePartA.append(unitChinese[j])                tnumChinesePartA.append(dictChinese[int(curr)])                bef = curr            if j == 3:                tnumChinesePartA.append(u'萬')                bef = '0'            j = j+1        for i in range(len(tnumChinesePartA)):            numChinesePartA.append(tnumChinesePartA.pop())    A = ''    for i in numChinesePartA:        A = A+i    #小数部分很简单，只要判断下角是否为零    B = ''    if len(strPartB) == 1:        B = dictChinese[int(strPartB[0])] + u'角'    if len(strPartB) == 2 and strPartB[0] != '0':        B = dictChinese[int(strPartB[0])] + u'角' + dictChinese[int(strPartB[1])] + u'分'    if len(strPartB) == 2 and strPartB[0] == '0':        B = dictChinese[int(strPartB[0])] + dictChinese[int(strPartB[1])] + u'分'    if len(strPartB) == 0:        S = A + u'圆整'    if len(strPartB)!= 0:        S = A + u'圆' +B    return S

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